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10(a) In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $20 \times 10 ^{10 }Hz$ and amplitude $48 Vm ^{-1}$

What is the wavelength of the wave?

Answers (1)

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Frequency( $\nu$ ) =20 $\times$ 10¹⁰ Hz

E₀ = 48 Vm^-1

$Wavelength(\lambda) =\frac{Speed\ of\ light(c)}{Frequency (\nu )}$

= $\frac{3\times 10^{8}}{20\times 10^{10}}$

$=1.5 mm$

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