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Q10.16 In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1°. What is the spacing between the two slits?

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Given,

Wavelength of light \lambda = 600nm 

Angular fringe width 

B_{\theta}=\frac{\lambda}{d}

d=\frac{\lambda}{B_{\theta}}=\frac{600*10^{-9}*180}{0.1*\pi }=3.44*10^{-4}m

Hence spacing required between the two slits is 3.44*10^{-4}m.

Posted by

Pankaj Sanodiya

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