4.12) In Exercise 4.11 obtain the frequency of revolution of the electron in its circular orbit. Does the answer depend on the speed of the electron? Explain

Answers (1)
S Sayak

In exercise 4.11 we saw r=\frac{eB}{mv}

Time taken in covering the circular path once(time period (T))=\frac{2\pi r}{v} =\frac{2\pi m}{eB}

Frequency, \nu =\frac{1}{T}=\frac{eB}{2\pi m}

From the above equation, we can see that this frequency is independent of the speed of the electron.

\nu =\frac{1.6\times 10^{-19}\times 4.8\times 10^{6}}{2\pi \times 9.1\times 10^{-31}}=18.2 MHz

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