Q : 4     In Fig. \small 10.38, \small \angle ABC=69^{\circ}, \angle ACB=31^{\circ},, find \small \angle BDC

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Answers (1)

In \triangle ABC,

        \angleA+\angleABC+\angleACB=180\degree

\Rightarrow \angle A+69 \degree+31 \degree=180\degree

\Rightarrow \angle A+100 \degree=180\degree

\Rightarrow \angle A=180 \degree-100\degree

\Rightarrow \angle A=80 \degree

\angleA  = \angleBDC = 80 \degree   (Angles in same segment)

 

 

 

 

 

 

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