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  • In Fig. 9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (ii) ar (AX S) = 1/2 ar (PQRS)

Q : 5        In Fig. \small 9.17, PQRS and ABRS are parallelograms and X is any point on side                    BR. Show that
               (ii)  \small ar(AXS)=\frac{1}{2}ar(PQRS)

                

Answers (1)

Now, AXS and ||gm ABRS are on the same base AS and between same parallels AS and BR

∴ area of AXS = 1/ 2 area of ABRS  

⇒ area of AXS = 1/ 2 area of PQRS [ ar (PQRS) = ar (ABRS)]  

⇒ ar of (AXS) = 1/ 2 ar of (PQRS)

Hence Proved

Posted by

Satyajeet Kumar

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