Q : 14 In Fig. , . Prove that .
We have, AP || BQ || CR
BCQ and BQR lie on the same base (BQ) and between same parallels (BQ and CR)
Therefore, ar (BCQ) = ar (BQR)........(i)
Similarly, ar (ABQ) = ar (PBQ) [common base BQ and BQ || AP]............(ii)
Add the eq(i) and (ii), we get
ar (AQC) = ar (PBR)