Q3. In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

 

Answers (1)

As we know that mL of red pigment is directly proportional to the mL of base.

We have to calculate for the mL of red pigment used when we mix 1800mL of base,

So, for 1 part of red pigment requires 75mL of base, then we

\frac{redpigment(mL)}{base(mL)}= \frac{1}{75} .

So for 1800mL of the base, mL of the red pigment should be mixed 

\frac{redpigment(mL)}{1800mL}= \frac{1}{75}     or     redpigment(mL)=\frac{1800mL}{75}=24mL

Hence for the 1800mL of base, we will mix 24 parts of red pigment.

 

 

Preparation Products

Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
Buy Now
Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Foundation 2021 Class 9th Maths

Master Maths with "Foundation course for class 9th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions