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header-bg qa

In the circuit shown in the figure, initially key K_{1} is closed and K_{2} is open. Then K_{1} is opened and K_{2} is closed. Then

a) charge on C_{1} gets redistributed i.e, V_{1}=V_{2}

b) charge on C_{1} gets redistributed i.e,\left ( Q_{1}+Q_{2} \right )=Q

c) charge on C_{1} gets redistributed such that Q_{1}=Q_{2}

d) charge on C_{1} gets redistributed such that C_{1}V_{1}+C_{2}V_{2}=C_{1}E

Answers (1)

The answer is the options,

a) charge on C_{1} gets redistributed such that V_{1}=V_{2}

d) charge on C_{1} gets redistributed such that \left ( Q_{1}+Q_{2} \right )=Q

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