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Let  \ast   be binary operation defined on R by a \ast b = 1 + ab, \forall a, b \in R. Then the operation \ast   is

(i) commutative but not associative

(ii) associative but not commutative

(iii) neither commutative nor associative

(iv) both commutative  and  associative
 

Answers (1)

(i) Here,  

\ast   is a binary operation defined on R by a \ast b = 1 + ab, \forall a, b \in R

So, a \ast b = ab + 1 = b \ast a\\

Therefore,  \ast   is a commutative binary operation.

\\Now, a \ast (b \ast c) = a \ast (1 + bc) = 1 + a (1 + bc) = 1 + a + abc\\ Again, (a \ast b) \ast c = (1 + ab) \ast c = 1 + (1 + ab) c = 1 + c + abc\\ Therefore, a \ast (b \ast c) \neq (a \ast b) \ast c\\

Hence,  \ast  is not associative.

Therefore,  \ast   is commutative but not associative.

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