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  • Let f : R → R be the functions defined by f(x) = x3 + 5. Then f-1(x) is (a) (x + 5)1/3

Let f : R \rightarrow R be the functions defined by f(x) = x\textsuperscript{3} + 5. Then f\textsuperscript{-1}(x) is

\\(a) (x + 5)\textsuperscript{1/3}\\ (b) (x - 5)\textsuperscript{1/3}\\ (c) (5 - x)\textsuperscript{1/3}\\ (d) 5 - x \\

Answers (1)

(b)Here,

\\f(x) = x\textsuperscript{3} + 5\\ Say, y = x\textsuperscript{3} + 5\\ or, x\textsuperscript{3} = y - 5 \\ or, x = (y - 5)\textsuperscript{1/3}\ f\textsuperscript{-1}1(x) = (x - 5)\textsuperscript{1/3} \\

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