Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • On dividing x raised to 3 minus 3x ^ 2 + x + 2 by a polynomial g(x), the quotient and remainder were x- 2 and - 2x + 4, respectively. Find g(x).

Q4 On dividingx^3 - 3x^2 + x + 2 by a polynomial g(x), the quotient and remainder were x – 2 and –2x + 4, respectively. Find g(x).

Answers (1)

Quotient = x-2

remainder =-2x+4

\\dividend=divisor\timesquotient+remainder\\x^3-3x^2+x+2=g(x)(x-2)+(-2x+4)\\x^3-3x^2+x+2-(-2x+4)=g(x)(x-2)\\x^3-3x^2+3x-2=g(x)(x-2)\\

g(x)=\frac{x^3-3x^2+3x-2}{x-2}

Carrying out the polynomial division as follows

g(x)={x^2-x+1}

Posted by

Safeer PP

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE to conduct Class 10, 12 practical board exams 2026-27 from November 9
anam-khan

CBSE opens LOC correction facility for Class 10, 12 board exams 2027; make changes by November 7
anam-khan

CBSE Date Sheet 2027 LIVE: Class 10, 12 subject-wise timetable soon; two board exam policy, grading system

Latest Question