Q.4 One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Let us assume that the units place of a two digit number is x.
Then as per the question, tens place of the number is 3x.
Thus the two digit number is 10(3x) + x.
If we interchange the digits the number becomes : 10x + 3x
According to the question,
10(3x) + x + 10x + 3x = 88
or 30x + 14x = 88
or 44x = 88
Dividing both sides by 44, we get
x = 2
Hence the two digit number is 10(6) + 2 = 62
Note that the two-digit number can also be found if we reverse the digits. So one more possible number is 26.