Q : 5         Show that.

                (iii)   (\frac{4}{3}m-\frac{3}{4}n)^2 +2mn=\frac{16}{9}m^2+\frac{9}{16}n^2

Answers (1)

First we will solve the LHS :

             = (\frac{4}{3}m-\frac{3}{4}n)^2 +2mn = \frac{16}{9}m^2 - 2mn + \frac{9}{16}n^2 + 2mn

or                = \frac{16}{9}m^2 + \frac{9}{16}n^2

                  =  RHS

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