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  • Show that the function given by f x is equal to 3x plus 17 is increasing on R.

1. Show that the function given by f (x) = 3x + 17 is increasing on R.

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Let   x_1 and x_2  are two numbers in R
x_1 < x_2 \Rightarrow 3x_1 < 3 x_2 \Rightarrow 3x_1 + 17 < 3x_2+17 \Rightarrow f(x_1)< f(x_2)
Hence, f is strictly increasing on R

Posted by

Gautam harsolia

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