Q : 4     Simplify. 

            (vi) (ab+bc)^2-2ab^2c

Answers (1)

We use identity
       (a+b)^{2} = a^{2} + 2ab + b^{2}
           In this a =  ab and b = bc
                              (ab+bc)^{2} = (ab)^{2} + 2(ab)(bc) + (bc)^{2}
                                                   = a^{2}b^{2} + 2ab^{2}c + b^{2}c^{2}
Now,    a^{2}b^{2} + 2ab^{2}c + b^{2}c^{2} - 2ab^{2}c
               =  a^{2}b^{2} + b^{2}c^{2}

Preparation Products

Knockout NEET Sept 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
Buy Now
Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
Buy Now
Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Test Series NEET Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 11999/-
Buy Now
Exams
Articles
Questions