Q2. Simplify and express the result in power notation with a positive exponent.

    (i)  (-4)^{5}\div (-4)^{8}

Answers (1)

The detailed solution for the above-written question is as follows

We know the exponential formula

\frac{a^{m}}{a_{n}} = a^{m-n}        and   a^{-m}= \frac{1}{a^{m}}

So according to this 

a = -4, m = 5 and n = 8

\frac{4^{5}}{4_{8}} = -4^{5-8} = -4^{-3}

                      = (-\frac{1}{4})\times -(\frac{1}{4})\times(-\frac{1}{4}) = -\frac{1}{64}

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