Q2. Simplify and express the result in power notation with a positive exponent.

    (iv)  (3^{-7}\div 3^{-10})\times 3^{-5}    

Answers (1)
M manish

The detailed explanation for the above-written question is as follows

As we know the exponential form 

\frac{a^{m}}{b^{n}}= a^{m-n} \& (a^{m}\times a^{n})=a^{m+n}

By using these two form we get,

\frac{3^{-7}}{3^{-10}}\times (3)^{-5}=3^{-7-(-10)} \times (3)^{-5} 

            =3^{3} \times (3)^{-5}= 3^{-2}

             =\frac{1}{3}\times \frac{1}{3}=\frac{1}{9}

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