# Simplify and solve the following linear equation.Q.9   3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17

Let us open the brackets.

LHS:      3(5z - 7) - 2(9z - 11)

=  15z - 21 - 18z + 22

=   -3z + 1

RHS:      4(8z - 13) - 17

= 32z - 52 - 17

= 32z - 69

So the equation becomes :   -3z + 1 = 32z - 69

or                           69 + 1 = 32z + 3z

or                               70 = 35z

z = 2

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