Solve the following equation and check your result.

Q.8 

                 \frac{2x}{3}+1 = \frac{7x}{15}+3

Answers (1)

We have

                                    \frac{2x}{3} + 1 = \frac{7x}{15} + 3

Transposing   \frac{7x}{15}   to the LHS and 1 to the RHS:

                                \frac{2x}{3} - \frac{7x}{15} = 3 - 1 = 2

or                               \frac{10x - 7x}{15} = 2

or                                        \frac{3x}{15} = 2

or                                        x = 10

Check  :- Put x = 10 in both the LHS and the RHS

                LHS : 

                                \frac{2x}{3} + 1 = \frac{2}{3}\times 10 + 1 = \frac{23}{3}

                RHS :

                                 \frac{7x}{15} + 3 = \frac{7}{15}\times 10 + 3 = \frac{14}{3} + 3 = \frac{23}{3}

Thus,                  LHS = RHS

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