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# Solve the following equation and check your result. 4z + 3 = 6 + 2z

Solve the following equation and check your result.

Q.4  4z + 3 = 6 + 2z

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We have

4z + 3 = 6 +2z

Transposing 2z to the LHS and 3 to the RHS, we get:

4z - 2z = 6 - 3

or                   2z = 3

DIviding both sides by 2,

$z = \frac{3}{2}$

Check:-  Put   $z = \frac{3}{2}$   in LHS as well as RHS, we have

LHS :-  4z + 3

$= 4\times \frac{3}{2} + 3 = 9$

RHS :-  6 + 2z

$= 6 + 2\times \frac{3}{2} = 6 + 3 = 9$

Thus,           LHS = RHS

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