Solve the following equations and check your results.

Q.9  

           2y+\frac{5}{3} = \frac{26}{3} -y                  

Answers (1)

We have 

                               2y+ \frac{5}{3} = \frac{26}{3} - y

Transposing -y to the LHS and  \frac{5}{3}  to the RHS, we get

                              2y + y = \frac{26}{3}- \frac{5}{3} = \frac{21}{3} = 7

or                                 3y  =  7 

Dividing both sides by 3:

                                y = \frac{7}{3}i

Check :-  Put    y = \frac{7}{3}  in both the LHS and the RHS:

               LHS :   

                               2y + \frac{5}{3} = 2\times \frac{7}{3} + \frac{5}{3} = \frac{19}{3}

               RHS : 

                               \frac{26}{3} - \frac{7}{3} = \frac{19}{3}

Hence,          LHS = RHS

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