Solve the following linear equations.

Q.1       \frac{x}{2}-\frac{1}{5} = \frac{x}{3}+\frac{1}{4}

Answers (1)

The detailed solution of the above-written question is here,

We have

                              \frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}

or                          \frac{x}{2} - \frac{x}{3} = \frac{1}{4} + \frac{1}{5}

 

or                         \frac{3x - 2x}{6} = \frac{4 +5}{20}

 

or                        \frac{x}{6} = \frac{9}{20}

Mutiplying both sides by 6:

                         x = \frac{9}{20}\times 6 = \frac{27}{10}

Thus               x = \frac{27}{10}

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