Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Suppose that the particle in is an electron projected with velocity vx 2 0 10 raise to 6 m s 1 If E between the plates separated by 0 5 cm is 9 1 multiply by 10 raise to 2 N upon C where will the electron strike the upper plate

1.34) Suppose that the particle in is an electron projected with velocity v_{x}=2.0 \times 10^{6}ms^{-1}. If E between the plates separated by 0.5 cm is 9.1 \times 10^{2}\frac{N}{C}, where will the electron strike the upper plate? (|e|=\left | e \right |=1.6 \times 10^{-19}, m_{e}=9.1\times 10^{-31}kg)

Answers (1)

\therefore The vertical deflection of the particle at the far edge of the plate is s=\frac{qEL^{2}}{2mv_{x}^{2}}

given s= 0.5cm=0.005cm

calculate for L from the above equation 

L=\sqrt{\frac{2smv_x^2}{qE}}=\sqrt{\frac{2\times 0.005\times 9.1\times 10^{-31}(2\times10^6)^2 }{1.6\times 10^{-19}\times9.1\times10^2}}

L=1.6 cm

 

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question