The activity R of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:
t(h) |
0 |
1 |
2 |
3 |
4 |
R(MBq) |
100 |
35.36 |
12.51 |
4.42 |
1.56 |
(i) Plot the graph of R versus t and calculate half-life from the graph.
(ii) Plot the graph of ln(R/R0) versus t and obtain the value of half-life from the graph.
From the above graph, we can clearly understand that 50% reduction of R has happened. Therefore, the value of the half-life is 40 mins.
In the graph, the value of t = OB, that is equal to 40 mins.
ii)
The above graph is ln(R/R0) versus t.
Here, the slope of the graph = –
Therefore, the value of = -(-4.16-3.11)/1 = 1.05 h-1
Now, Half-time(T1/2) = 0.693/ = 0.66 h = 39.6 min