Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The activity R of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows: t(h) 0 1 2 3 4 R(MBq) 100 35.36 12.51 4.42 1.56 (i) Plot the graph of R versus t and calculate half-life from the graph.

 The activity R of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:

t(h)

0

1

2

3

4

R(MBq)

100

35.36

12.51

4.42

1.56

(i) Plot the graph of R versus t and calculate half-life from the graph.

(ii) Plot the graph of ln(R/R0) versus t and obtain the value of half-life from the graph.

Answers (1)

Explanation:-

(i) From the above graph,

- we can clearly understand that a 50% reduction of R has happened. Therefore, the value of the half-life is 40 mins.

- In the graph, the value of t = OB, is equal to 40 mins.

 

ii)

 

The above graph is ln(R/R0) versus t.

Here, the slope of the graph = – \lambda

Therefore, the value of \lambda = -(-4.16-3.11)/1 = 1.05 h-1

Now, Half-time(T1/2) = 0.693/ \lambda = 0.66 h = 39.6 min

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question