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A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1 =N2 and Z2 =N1.

(a) What nuclide is a mirror isobar of   2311 Na?

(b) Which nuclide out of the two mirror isobars have greater binding energy and why?

Answers (1)

a) We can understand that a nuclide of 1 must be the mirror isobar of nuclide 2, when: Z1 = N2 and Z2 = N1

As a result, the mirror isobar is Z2 = 12 – N1

Similarly, N2 = 23 -12 = 11 = Z1

b) The binding energy of Mg is greater than Na.

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