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 The activity R of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:

t(h)

0

1

2

3

4

R(MBq)

100

35.36

12.51

4.42

1.56

(i) Plot the graph of R versus t and calculate half-life from the graph.

(ii) Plot the graph of ln(R/R0) versus t and obtain the value of half-life from the graph.

Answers (1)

From the above graph, we can clearly understand that 50% reduction of R has happened. Therefore, the value of the half-life is 40 mins.

In the graph, the value of t = OB, that is equal to 40 mins.

ii)

 

The above graph is ln(R/R0) versus t.

Here, the slope of the graph = – \lambda

Therefore, the value of \lambda = -(-4.16-3.11)/1 = 1.05 h-1

Now, Half-time(T1/2) = 0.693/ \lambda = 0.66 h = 39.6 min

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