Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The area of a trapezium is 475 cm^{2} and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

The area of a trapezium is 475 cm^{2} and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

Answers (1)

\left [ 23 \; cm, 27\; cm \right ]

Let the smaller parallel side be CD = x cm

                                            

Then other parallel side AB = (x + 4) cm

Given, area of trapezium = 475 cm^{2}

Height DE = 19 cm

We \; know \; that, \; Area \; of \: trapezium = \frac{1}{2} \times height \times (sum\; of \; parallel \; sides)

475= \frac{1}{2}\times DE\times \left ( DC+AB \right )

475\times 2= 19\times \left ( x+x+4 \right )

\frac{475\times 2}{19}= 2x+4

25 \times 2 = 2x + 4

50 = 2x + 4

50 - 4 = 2x

46 = 2x

x= \frac{46}{2}

x = 23 cm

So the smaller side CD is 23 cm and other parallel side AB is (23 + 4) cm = 27 cm

 

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question