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  • The area of a trapezium is 475 cm^{2} and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

The area of a trapezium is 475 cm2 and the height is 19 cm . Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

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Solution

Let the smaller parallel side be CD=x cm

                  

Then other parallel side AB=(x+4)cm
Given, area of trapezium =475 cm2
Height DE =19 cm
We know that, Area oftrapezium =12× height ×( sum of parallel sides )

475=12×DE×(DC+AB)475×2=19×(x+x+4)

475×219=2x+425×2=2x+450=2x+450−4=2x46=2xx=462x=23 cm

So the smaller side CD is 23 cm and the other parallel side AB is (23+4) cm = 27 cm

 

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infoexpert21

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