Q.3 The base of an isosceles triangle is  \frac{4}{3}  cm. The perimeter of the triangle is  4\frac{2}{15} cm . What is the length of either of the remaining equal sides?

Answers (1)

In isosceles triangles, we have 2 sides of equal length.

Given that its perimeter is   \frac{62}{15}  cm.

Let's assume the length of the equal side is x cm.

Also, 

Perimeter = x + x + \frac{4}{3} = \frac{62}{15}

Transposing  \frac{4}{3} to the RHS side it becomes,

  2x = \frac{62}{15}-\frac{4}{3} = \frac{62-20}{15} = \frac{42}{15} = \frac{14}{5}

Now dividing both sides by 2, we get

  x = \frac{14}{5}\times \frac{1}{2} = \frac{7}{5}

Hence, the length of the equal sides of the isosceles triangle is   \frac{7}{5}  cm.

 

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions