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  • The base of an isosceles triangle is  4/3 cm. The perimeter of the triangle is 62/15 cm. What is the length of either of the remaining equal sides?

Q.3 The base of an isosceles triangle is  \frac{4}{3}  cm. The perimeter of the triangle is  4\frac{2}{15} cm . What is the length of either of the remaining equal sides?

Answers (1)

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In isosceles triangles, we have 2 sides of equal length.

Given that its perimeter is   \frac{62}{15}  cm.

Let's assume the length of the equal side is x cm.

Also, 

Perimeter = x + x + \frac{4}{3} = \frac{62}{15}

Transposing  \frac{4}{3} to the RHS side it becomes,

  2x = \frac{62}{15}-\frac{4}{3} = \frac{62-20}{15} = \frac{42}{15} = \frac{14}{5}

Now dividing both sides by 2, we get

  x = \frac{14}{5}\times \frac{1}{2} = \frac{7}{5}

Hence, the length of the equal sides of the isosceles triangle is   \frac{7}{5}  cm.

 

Posted by

Divya Prakash Singh

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