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The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8, 5.0, 4.2, 2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each

7.56     The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8, 5.0, 4.2, 2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each

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M manish

We already know that p^H can be calculated as- -\log[H^+] 
to calculate the concentration of [H^+] = antilog (-p^H)

Thus, the hydrogen ion concentration of followings p^H values are-

(i)  p^Hof milk = 6.8
Since, p^H=-\log[H^+]
6.8 = -\log[H^+]
\log[H^+] = -6.8

[H^+] = anitlog(-6.8)

        = 1.5\times10^{-7}M

 

(ii) p^Hof black coffee = 5.0

Since, p^H=-\log[H^+]

5.0 =-\log[H^+]

\log[H^+]= -5.0

[H^+]= anitlog(-5.0)

= 10^{-5}M

 

(iii) p^H of tomato juice = 4.2

Since, p^H=-\log[H^+]

4.2 =-\log[H^+]

\log[H^+]= -4.2

[H^+]= anitlog(-4.2)

= 6.31\times10^{-5}M

 

(iv) p^H of lemon juice = 2.2

Since, p^H=-\log[H^+]

2.2 = -\log[H^+]

\log[H^+]= -2.2

[H^+]= anitlog(-2.2)

=6.31\times10^{-3}M

(v) p^H of egg white = 7.8

Since, p^H=-\log[H^+]

7.8 = -\log[H^+]

\log[H^+] = -7.8

[H^+]= anitlog(-7.8)

= 1.58\times10^{-8}M

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