Get Answers to all your Questions

header-bg qa

Q. 14.14 The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m If the piston moves with simple harmonic motion with an angular frequency of  200\; rad/min,  what is its maximum speed ?

Answers (1)


Amplitude of SHM = 0.5 m

angular frequency is

\\\omega =200\ rad/min \\\omega =3.33\ rad/s

If the equation of SHM is given by

\\x(t)=Asin(\omega t+\phi )\\

The velocity would be given by

\\v(t)=\frac{\mathrm{d} x(t)}{\mathrm{d} t}\\ v(t)=\frac{\mathrm{d} (Asin(\omega t+\phi ))}{\mathrm{d} t}\\ v(t)=A\omega cos(\omega t+\phi )

The maximum speed is therefore

\\v_{max}=A\omega \\ v_{max}=0.5\times 3.33 \\v_{max}=1.67ms^{-1}

Posted by


View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support