2.26 The plates of a parallel plate capacitor have an area of 90 cm2 each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply.

(a) How much electrostatic energy is stored by the capacitor?

 

Answers (1)

Here 

The capacitance of the parallel plate capacitor :

C=\frac{\epsilon_0 A}{d}

 

The Electrostatic energy stored in the capacitor is given by :

E=\frac{1}{2}CV^2=\frac{1}{2}\frac{\varepsilon _0A}{d}V^2 =\frac{1.885*10^{-12}90*10^{-4}*400^2}{2*2.5*10^{-3}}=2.55*10^{-6}J

Hence, the electrostatic energy stored by the capacitor is 2.55*10^{-6}J.

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