Q.7 The sum of three consecutive multiples of 8 is 888. Find the multiples.

Answers (1)

Let x be the multiple of 8.

Then the three consecutive integers (multiple of 8) are x, x+8, x+16.

Given their sum is 888,

thus the equation becomes: x + x + 8 + x + 16 = 888

or          3x + 24 = 888

Transposing 24 to the RHS 

            3x = 888 - 24 = 864

Now dividing both sides by 3, we get

      x = \frac{864}{3} = 288

Thus the required consecutive integers are 288, 296, 304. 

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