# The surface tension and vapour pressure of water at is and  Pa, respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at ?

In case when the water pressure in the liquid is greater than the surface above the liquid, the drop will evaporate. We assume R to be the radius of the droplet before evaporation.

We know that pressure of vapour = pressure which becomes excess inside the drop

$/P$  $=\frac{2 \times 7.28 \times 10^{-2}}{2.33 \times 1000 }= \frac{14560}{233}\times 100000$

Hence,

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