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Q: 11.2 (c) The work function of caesium metal is2.14\hspace{1mm}eV. When light of frequency 6\times 10^1^4\hspace{1mm}Hz is   incident on the metal surface, photoemission of electrons occurs. What is the maximum speed of the emitted photoelectrons? 

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The electrons with the maximum kinetic energy of 0.34 eV will have the maximum speed

\\KE_{max}=0.34\ eV\\ KE_{max}=5.44\times 10^{-20}\ J\\ v_{max}=\sqrt{\frac{2KE_{max}}{m}}\\v_{max}=\sqrt{\frac{2\times 5.44\times 10^{-20}}{9.1\times 10^{-31}}}\\v_{max}=3.44\times 10^{5}\ ms^{-1}

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