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  • There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

6.    There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

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 There are four men and six women on the city council

 \therefore n(S) = n(men) + n(women) = 4 + 6 = 10

Let E be the event of selecting a woman

\therefore n(E) = 6

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{6}{10} = \frac{3}{5}

Therefore, the required probability of selecting a woman is 0.6

Posted by

HARSH KANKARIA

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