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10.    There are two types of fertilisers F1 and F2 . F1 consists of 10% nitrogen and 6% phosphoric acid and F2 consists of 5% nitrogen and 10% phosphoric acid. After testing the soil conditions, a farmer finds that she needs atleast 14 kg of nitrogen and 14 kg of phosphoric acid for her crop. If F1 costs Rs 6/kg and F2 costs Rs 5/kg, determine how much of each type of fertiliser should be used so that nutrient requirements are met at a minimum cost. What is the minimum cost?

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Let farmer buy x kg of fertilizer F1 and y kg of F2  .Thus, x\geq 0,y\geq 0.

The given information can be represented in table as :

  Nitrogen phosphoric acid  Cost 
F1   10     6     6
F2    5      10      5
 requirement     14     14  

F1 contain 10% nitrogen and F2 contain 5% nitrogen .Farmer requires atleast 14 kg of nitrogen 

               10\%x+5\%y\geq 14

                   \frac{x}{10}+\frac{y}{20}\geq 14

               2x+y\geq 280

F1 contain 6% phophoric acid  and F2 contain 10% phosphoric acid  .Farmer requires atleast 14 kg of nitrogen 

               6\%x+10\%y\geq 14

                   \frac{6x}{100}+\frac{y}{20}\geq 14

               3x+56y\geq 700

Total cost is  Z . Z=6x+5y

Subject to constraint ,

               2x+y\geq 280

               3x+56y\geq 700

                x\geq 0,y\geq 0

             Z=6x+5y

The feasible  region determined by constraints is as follows:

    

It can be seen that feasible region is unbounded.

The corner points of feasible region are A(\frac{700}{3},0),B(100,80),C(0,280)

The value of Z at corner points is as shown :

 corner points 

Z=6x+5y

 
   A(\frac{700}{3},0)             1400  

,B(100,80)

           1000 minimum
C(0,280)             1400  

 

 

  Feasible region is unbounded , therefore 1000 may or may not be minimum value of Z .

For this we draw 6x+5y< 1000 and check whether resulting half plane has point in common with feasible region or not.

We can see feasible region has no common point with  6x+5y< 1000.

Hence , Z has minimum value 1000  at  point  ,B(100,80)

Posted by

seema garhwal

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