Q.6 Three consecutive integers add up to 51. What are these integers?
Let the consecutive integers be x, x+1, x+2.
Sum of these integers is given to be 51.
Thus equation becomes : x + x + 1 + x + 2 = 51
3x + 3 = 51
Transposing 3 to the RHS,
3x = 48
Now dividing both sides by 3, we get
Hence the consecutive integers are 16, 17, 18.
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