Q.6 Three consecutive integers add up to 51. What are these integers?

Answers (1)

Let the consecutive integers be x, x+1, x+2.

Sum of these integers is given to be 51.

Thus equation becomes :  x + x + 1 + x + 2 = 51

      3x + 3 = 51

Transposing 3 to the RHS,

      3x = 48

Now dividing both sides by 3, we get 

   x = \frac{48}{3} = 16

Hence the consecutive integers are 16, 17, 18. 

 

 

 

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