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  • Two masses of 5 kg and 3 kg are suspended with help of massless inextensible strings as shown in the figure. Calculate T^1 and T^2 when whole system is going upwards with acceleration = 2 m/s^2.

Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in the figure. Calculate T_{1} and T_{2} when whole system is going upwards with acceleration = 2 m/s2.

Answers (1)

We know that the whole system is going up with acceleration, a = 2ms^{-2}

In all parts of the string, tension is equal and opposite.

The forces acting on mass m1 –

T_{1} - T_{2} - m_{1}g = m_{1}a

T_{1} - T_{2} - 5g = 5a

T_{1} - T_{2} = 5g+ 5a

T_{1} - T_{2} = 5(9.8 + 2) = 5 \times 11.8

T_{1} - T_{2} = 59N

The forces acting on mass m2 –

T_{2} - m_{2}g = m_{2}a

T_{2} = m_{2}(g+a)

   T_2  =3 (9.8 + 2) = 3(11.8)  = 35.4

Now, T_{1} = T_{2} + 59

             T_1   = 35.4 + 59

Thus, T_{1} = 94.4 N

Hence, T_{1} = 94.4 N and T_2 =35.4 

Posted by

infoexpert24

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