# Q : 1   Use a suitable identity to get each of the following products in bracket.           (iv)    $(3a - \frac{1}{2}) (3a -\frac{1}{2} )$

$(3a - \frac{1}{2}) \times (3a -\frac{1}{2} ) = ((3a - \frac{1}{2}))^{2}$
We use identity II for this which is
$(a-b)^{2} = a^{2} -2ab + b^{2}$
in this a = 3a and b = -1/2
$(3a-\frac{1}{2})^{2} = (3a)^{2} -2(3a)(\frac{1}{2}) + (\frac{1}{2})^{2}$
= $9a^{2} -3a + \frac{1}{4}$

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