Q : 8   Using  (x+a)(x+b)=x^2+(a+b)x+ab , find

           (i) 103 \times 104

Answers (1)

We know,

(x+a)(x+b)=x^2+(a+b)x+ab

Using this formula,

103 \times 104 = (100 + 3)(100 + 4) 

Here x =100, a = 3, b = 4

\therefore 103 \times 104  = 100^2+(3+4)100+(3\times4)

= 10000+1200+12

= 11212

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