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  • Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: a n = 2 n - 3 / 6

4.  Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are:

     a _n = \frac{2n-3 }{6}

Answers (1)

best_answer

Given : a _n = \frac{2n-3 }{6}

a _1 = \frac{2\times 1-3 }{6}=\frac{-1}{6}

a _2 = \frac{2\times 2-3 }{6}=\frac{1}{6}

a _3 = \frac{2\times 3-3 }{6}=\frac{3}{6}=\frac{1}{2}

a _4 = \frac{2\times 4-3 }{6}=\frac{5}{6}

a _5 = \frac{2\times 5-3 }{6}=\frac{7}{6}

Therefore, the required number of terms =\frac{-1}{6},\frac{1}{6},\frac{1}{2},\frac{5}{6},\frac{7}{6}

Posted by

seema garhwal

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