A fighter plane flying horizontally at an altitude of 1.5 km with speed 720 km/h passes directly over an anti-aircraft gun. At what angle from the vertical should the gun be fired for the shell with muzzle speed 600 m s-1 to hit the plane? At what minimum altitude should the pilot fly the plane to avoid being hit? (Take g = 10 m s-2)

Answers (1)

According to the question the situation is shown below:-  

                                           Motion in a plane ,    20241

Now,  The horizontal distance travelled by the shell  =  Distance travelled by plane

or                                         u sin Theta  t = vt

or                                              sin Theta  = fracvu

or                                                             = frac200600

So,                                                   Theta  = 19.5^circ

So, the required height will be:- 

                                                   H = fracu^2 sin^2(90 - Theta )2g

or                                                       = frac600^2 cos^2 Theta 2g

or                                                       = 16006.48 m

or                                                       = 16 Km

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