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1+2+3+4+5+6............+100 Solve by Formula(A.P)

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$S= 1+2+3....+100 \\ $ Above series is in A.P. \\ a = 1, d=1 , n=100 $\\\\ S_n = \frac{n}{2} \{ 2a +(n-1)d \} \\\\ S_n = \frac{100}{2} \{ 2\times 1 +(100-1)1 \} \\\\ S_n = \frac{100}{2} \{ 2\times 1 +(100-1)1 \} \\\\ S_n = 50 \times 101 = 5050 \\\\$

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Ravindra Pindel

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