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  • 1. The equation of the perpendicular bisector of the line segment joining the points (1, 2), (3, 4) is. [ ]a) 2x – y + 5 = 0 b) x + y – 4 = 0 c) 3x – 2y + 5 = 0 d) x + y – 5 = 0?Please give Step by Step Explanation..please I will mark as brainleis

1. The equation of the perpendicular bisector of the line segment joining the points (1, 2), (3, 4) is. [ ]a) 2x – y + 5 = 0 b) x + y – 4 = 0 c) 3x – 2y + 5 = 0 d) x + y – 5 = 0?Please give Step by Step Explanation..please I will mark as brainleist answer

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Slope of the line joining the points (1,2) and (3,4)-

eginaligned &mathrmm_1=fracmathrmy_2-mathrmy_1mathrmx_2-mathrmx_1=frac4-23-1=frac22=1\ & ext Therefore, \ &mathbfm_mathbf1 mathbfm_mathbf2=-mathbf1\ &Rightarrow mathbfm_2=frac-1m_1=-1 endaligned

Also mid-point of the line joining the points (1,2) and (3,4)-
(mathrmh, mathrmk)=left(frac3+12, frac4+22 ight)=(2,3)
Equation of perependicular bisector
eginarrayl =mathbfy-mathbf3=-mathbf1(mathbfx-mathbf2) \ =mathbfy-mathbf3=mathbf2-mathbfx=mathbfx+mathbfy-mathbf5=mathbf0 endarray
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Deependra Verma

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