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  • [{(-2/5)^-7 x (-2/5)^9}/(-2/5)^2] and express the result as a power of 5

[{(-2/5)^-7 x (-2/5)^9}/(-2/5)^2] and express the result as a power of 5

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[\frac{(\frac{-2}{5})^{-7} \times (\frac{-2}{5})^9}{(\frac{-2}{5})^2}]\\\\= [\frac{(\frac{-2}{5})^{-7+9}}{(\frac{-2}{5})^2}]\\\\= 1\\\\=5^0

Posted by

Ravindra Pindel

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