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(3 + 2âˆš2) / (3 - âˆš2) = x + y âˆš2 Find the value of x and y

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$$ Given $ \frac{3 + 2\sqrt{2}}{3 - 2\sqrt{2}} = x + y\sqrt{2} \\\\ \frac{3 + 2\sqrt{2}}{3 - 2\sqrt{2}} \times \frac{3 + 2\sqrt{2}}{3 +2\sqrt{2}}= x + y\sqrt{2}\\\\ \frac{9 +8 +4\sqrt{2}}{9 - 8} = x + y\sqrt{2}\\\\ 17 +4\sqrt{2} = x + y\sqrt{2}\\\\ x =17, \ y =4$

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Ravindra Pindel

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