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{âˆš32-âˆš5}^â…“*{âˆš32+âˆš5}^â…“

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$=(\sqrt{32}-\sqrt{5})^{\frac{1}{3}} \times (\sqrt{32}+\sqrt{5})^{\frac{1}{3}} \\ =[(\sqrt{32}-\sqrt{5}) \times (\sqrt{32}+\sqrt{5})]^{\frac{1}{3}} \\ = (32-5)^\frac{1}{3}\\ =(27)^\frac{1}{3}\\ =(3^3)^\frac{1}{3}\\ =3$

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Ravindra Pindel

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