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(-321)x [(+603)x? ]=[(-321)x(+603)]x?=0?

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(-321)	imes[(+603)	imes ?]=[(-321)	imes?]	imes(+603)=0

Let unknown is x

(-321)	imes[(+603)	imes x]=[(-321)	imes x]	imes(+603)=0

(-321)	imes[(+603)	imes x]=0

x=frac0(-321)	imes(+603)

x=0

 

[(-321)	imes x]	imes(+603)=0

x=frac0(-321)	imes(+603)

x=0

So unknown must be 0

Posted by

Deependra Verma

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