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  • A 10 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. The distance of the object from the lens is 18 cm. Find the nature, position and size of the image formed.    <div styl

A 10 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. The distance of the object from the lens is 18 cm. Find the nature, position and size of the image formed. 

 

 

 

 
 
 
 
 

Answers (1)

Focal length = 12 cm = f

Distance of object lens = u = -18 cm

Object height = h = 10 cm

Convex lens :

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}

\frac{1}{v}=\frac{1}{f} + \frac{1}{u}

\frac{1}{v}=\frac{1}{12} + \frac{1}{(-18)}

v = 36cm

m = \frac{v}{u}=\frac{h'}{h}

m = \frac{36}{-18}=\frac{h'}{10}

h' = -20cm (size of the image)

Nature of the image is Real and inverted.

Posted by

Sumit Saini

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