# A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:

A’s 1 day’s work = $\frac{1}{24}$
B’s 1 day’s work = $\frac{1}{6}$
C’s 1 day’s work = $\frac{1}{12}$
(A+B+C)’s 1 day’s work = $\frac{1}{24}+\frac{1}{6}+\frac{1}{12}=\frac{1+4+2}{24}=\frac{7}{24}$
∴ The work will be completed by them in $\frac{24}{7}$ i.e. $3\frac{3}{7}$ days.

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